duthehustle93
Well-Known Member
- duthehustle93 Well-Known Member
Hi All,
I'm wiring in a 6 pole kill switch now, and I need to find a circuit that I can open to turn off the car. I'm installing the kill switch next to the ignition switch so an obvious choice would be to kill one of the ignition switch wires, but I'm really struggling with this complicated ignition switch. I read through @ctuinstra push button thread twice and I can't figure it which singular wire I can open to kill the car. VATS hasn't been disabled and I don't plan to... maybe I can use that to my advantage?
I know the following:
pin 1: not used
pin 2: red/white: 12V constant
pin 3: yellow: receives 12V from pin 2 when ignition switch is in 2nd position
pin 4: brown: receives 12V from pin 2 when ignition switch is in 1st or 2nd position.
pin 5: white: 12V from pin 2 when key is in, 0V/open in 1st position, switches to and pulls down 5V reference voltage (from pin 6) across the theft resistor in 2nd position
pin 6: white/black: reference 5V
So... the reasonable conclusion I came to was open pin 2 to open ignition. I cut the red/white (pin 2) wire, and the ignition switch cycles through perfectly like nothing happened, I can even start and run the car! My next reasonable conclusion was to reconnect the red/white wire I cut, and use the white/black (pin 6) wire... I cut that one... and same thing! Ignition switch cycles perfectly and I can even start the car! I can start the car, and open either of these with no ignition kill. I must open both pin 2 and pin 6 in order to kill the car. I only have 1 available pole on my kill switch, and obviously I can't combine 12V and 5V on a single switch. I would really prefer to keep my kill switch simple and not have a secondary relay or a voltage converter, it can't be that complicated, right?
Is there a single wire on the ignition switch or VATS that I can open to turn off the car? Alternatively, is there anything wrong with leaving my 5V white/black (pin 6) wire severed, and I can switch red/white (pin 2)? Everything seems "fine" with the latter route, but purposely severing a circuit that (probably) has a purpose feels like the wrong way to do this.
I'm wiring in a 6 pole kill switch now, and I need to find a circuit that I can open to turn off the car. I'm installing the kill switch next to the ignition switch so an obvious choice would be to kill one of the ignition switch wires, but I'm really struggling with this complicated ignition switch. I read through @ctuinstra push button thread twice and I can't figure it which singular wire I can open to kill the car. VATS hasn't been disabled and I don't plan to... maybe I can use that to my advantage?
I know the following:
pin 1: not used
pin 2: red/white: 12V constant
pin 3: yellow: receives 12V from pin 2 when ignition switch is in 2nd position
pin 4: brown: receives 12V from pin 2 when ignition switch is in 1st or 2nd position.
pin 5: white: 12V from pin 2 when key is in, 0V/open in 1st position, switches to and pulls down 5V reference voltage (from pin 6) across the theft resistor in 2nd position
pin 6: white/black: reference 5V
So... the reasonable conclusion I came to was open pin 2 to open ignition. I cut the red/white (pin 2) wire, and the ignition switch cycles through perfectly like nothing happened, I can even start and run the car! My next reasonable conclusion was to reconnect the red/white wire I cut, and use the white/black (pin 6) wire... I cut that one... and same thing! Ignition switch cycles perfectly and I can even start the car! I can start the car, and open either of these with no ignition kill. I must open both pin 2 and pin 6 in order to kill the car. I only have 1 available pole on my kill switch, and obviously I can't combine 12V and 5V on a single switch. I would really prefer to keep my kill switch simple and not have a secondary relay or a voltage converter, it can't be that complicated, right?
Is there a single wire on the ignition switch or VATS that I can open to turn off the car? Alternatively, is there anything wrong with leaving my 5V white/black (pin 6) wire severed, and I can switch red/white (pin 2)? Everything seems "fine" with the latter route, but purposely severing a circuit that (probably) has a purpose feels like the wrong way to do this.
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